A fog particle falling vertically through air experiences a downward force due to gravity. This force causes the particle to accelerate downward. According to Newton’s second law of motion, the net force acting on an object is equal to the mass of the object multiplied by its acceleration. In this case, the mass of the fog particle remains constant, so we can express the equation as:
Force due to gravity = Mass of fog particle × Acceleration
The force due to gravity can be calculated using the formula:
Force due to gravity = Mass of fog particle × gravitational acceleration
where the gravitational acceleration on Earth is approximately 9.8 meters per second squared (9.8 m/s^2).
Since the particle is falling vertically, the acceleration is equal to the acceleration due to gravity. Therefore, the acceleration of the fog particle is 9.8 m/s^2, and it remains constant as long as no other forces act upon it.
It’s important to note that other factors such as air resistance and the size, shape, and density of the fog particle can affect its motion through the air. If air resistance is significant, it can oppose the motion and result in a different acceleration than the gravitational acceleration. However, for small fog particles, air resistance is generally minimal, and the acceleration due to gravity can be considered the dominant force.